15s^2-48-48s=0

Solution for 15s^2-48-48s=0 equation:

15s^2-48-48s=0

a = 15; b = -48; c = -48;
Δ = b2-4ac
Δ = -482-4·15·(-48)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-72}{2*15}=\frac{-24}{30}
=-4/5
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+72}{2*15}=\frac{120}{30}
=4
$